5v^2-31v+4=28

Solution for 5v^2-31v+4=28 equation:

5v^2-31v+4=28

We move all terms to the left:

5v^2-31v+4-(28)=0

We add all the numbers together, and all the variables

5v^2-31v-24=0

a = 5; b = -31; c = -24;
Δ = b2-4ac
Δ = -312-4·5·(-24)
Δ = 1441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{1441}}{2*5}=\frac{31-\sqrt{1441}}{10}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{1441}}{2*5}=\frac{31+\sqrt{1441}}{10}
$